(4x^2+1)(4x-4)=0

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Solution for (4x^2+1)(4x-4)=0 equation: 


Simplifying
(4x2 + 1)(4x + -4) = 0

Reorder the terms:
(1 + 4x2)(4x + -4) = 0

Reorder the terms:
(1 + 4x2)(-4 + 4x) = 0

Multiply (1 + 4x2) * (-4 + 4x)
(1(-4 + 4x) + 4x2 * (-4 + 4x)) = 0
((-4 * 1 + 4x * 1) + 4x2 * (-4 + 4x)) = 0
((-4 + 4x) + 4x2 * (-4 + 4x)) = 0
(-4 + 4x + (-4 * 4x2 + 4x * 4x2)) = 0
(-4 + 4x + (-16x2 + 16x3)) = 0
(-4 + 4x + -16x2 + 16x3) = 0

Solving
-4 + 4x + -16x2 + 16x3 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '4'.
4(-1 + x + -4x2 + 4x3) = 0

Ignore the factor 4.

Subproblem 1
Set the factor '(-1 + x + -4x2 + 4x3)' equal to zero and attempt to solve:

Simplifying
-1 + x + -4x2 + 4x3 = 0

Solving
-1 + x + -4x2 + 4x3 = 0

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

The solution to this equation could not be determined.

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